Code As Trees

int main() {

char c;
int i;
int even;
i=0;
even=0;
while (i < 10) {
i = i+1;
if (i == (i/2)*2) {
even = even +1;
}
}
i = even + 23;

}


EditHint: Unfinished? Explanation requested.


See also: AbstractSyntaxTree.